While watching a small fireworks display from a building 204 feet tall, you observe a rocket that travels from ground to eye level in 6 seconds, and explodes. What is the maximum speed that you can guarantee that the rocket reached?
Is there a formula for velocity?
distance/t?
I was thinking of Galileo's equation(s).
oh
https://sites.google.com/site/urbangeekclassroomsg/using-word-documents/chapter-2-speed-velocity-and-acceleration s(t)=ut+.5*at^2 a is acceleration u is the initial velocity t is time s is the distance going up since we are going up
so we have to solve for u?
It looks like we can find the final velocity of this situation...but we need the initial velocity.
how would we find that?
do we have to take the derivative?
I think we can say the initial velocity is 0 since we started there.
ok
we also dont know the acceleration
acceleration would be \[\frac{ \delta V_f-\delta V _i}{t_f-t_i}\]
That is the change of velocity over the change of time
we dont know v final?
that would be the acceleration
we do know v final
we said it earlier
i said we could find it pretty easily didn't actually say the number
v final is the whole quation?
know max v not final v
no*
im confused :P
final v=final speed=distance/time
the speed isn't a constant
that is why we have this function of time that s function
ok
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