Question

Consider the line that passes through the point (3, -2) and has a slope of 2.
Part 1: Write the equation of this line using point-slope form.
Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form.
Part 3: Using your equation from part 2, rewrite this equation in standard form.

Answer 1

start with
\[y-y_1=m(x-x_1)\] with \[x_1=3,y_1=-2, m=2\] to get the "point slope" form

Answer 2

y - (-2) = 2(x - 3)?

Answer 3

yes, but you probably want to write
\[y+2=2(x-3)\] that is the "point slope" form
to turn that into the "slope intercept" form, solve the above equation for \(y\)

Answer 4

y = mx + b
y = 2/-3x + 2?
Did I do it right?

Answer 5

no

Answer 6

\[y+2=2(x-3)\] steps always the same
1) remove the parentheses using the distributive law on the right
\[y+2=2x-6\] then subtract \(2\) from both sides
\[y=2x-8\]