factor f(x) into linear factors given that k is a zero of f(x): f(x)=x^4+3x^3-12x^2-52x-48; k= -2 (multiplicity of 2) alright I know how to factor that out, but..... what is -2 multiplicity of 2?
it means that k is a double zero.
ie f(x)=(x+2)^2*p(x)
I am so lost k is a double zero? what does that do to the factoring of -2 then?
have you learned polynomial division yet?
yes we have but no where in my notes book anything can I find reference to multiplicity of the k value
the k value of 2 means that k is a zero both of f(x) and of f(k)/(x-k)
for example, the polynomial x^2+2x+1 has a zero k=-1 with multiplicity 2
since it can be written as (x+1)^2.
when everything is factored out I come up with f(x)=(x+2)(x^3+x^2-14x-24 does that seem right?
yes. now divide x^3+x^2-14x-24 by x+2 again.
x^2-x-12? Thank you soooooooooo much
;)
also don't forget to factor that
into (x+3)(x-4)
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