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The value of the integral is?
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dot dot dot....
\[\Huge \int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \frac{\sin^2x}{1+2^x}dx\]
I think it's 0.4317
nope
@hartnn
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king's rule is goona work here
do you what is that?
:O no
replaze x by (upper limit+lower limit -x) and those two limits will be equal....name them both S.....then add both equations
oh i know that,didnt knew the name or such
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so tried that?
it will give me the question itself
okay no
\[\Huge \int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}2^x \frac{\sin^2x}{1+2^x}dx\]
2^x +1 will cancel out
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add both the integrals
\[\Huge 2I=\int\limits_{\frac{-\pi}{2}}^{\frac{\pi}{2}}\sin^2xdx\]
Thank you :)
no prob... (:
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