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Mathematics 8 Online
OpenStudy (anonymous):

The value of the integral is?

OpenStudy (anonymous):

dot dot dot....

OpenStudy (anonymous):

\[\Huge \int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \frac{\sin^2x}{1+2^x}dx\]

OpenStudy (anonymous):

I think it's 0.4317

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

king's rule is goona work here

OpenStudy (anonymous):

do you what is that?

OpenStudy (anonymous):

:O no

OpenStudy (anonymous):

replaze x by (upper limit+lower limit -x) and those two limits will be equal....name them both S.....then add both equations

OpenStudy (anonymous):

oh i know that,didnt knew the name or such

OpenStudy (anonymous):

so tried that?

OpenStudy (anonymous):

it will give me the question itself

OpenStudy (anonymous):

okay no

OpenStudy (anonymous):

\[\Huge \int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}2^x \frac{\sin^2x}{1+2^x}dx\]

OpenStudy (anonymous):

2^x +1 will cancel out

OpenStudy (anonymous):

add both the integrals

OpenStudy (anonymous):

\[\Huge 2I=\int\limits_{\frac{-\pi}{2}}^{\frac{\pi}{2}}\sin^2xdx\]

OpenStudy (anonymous):

Thank you :)

OpenStudy (anonymous):

no prob... (:

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