Question

the roots of x^3+6x^2-12x+32=0 were reduced by h to obtain a new cubic equation with no second degree term then h=?

Answer 1

let the root be 'x'
it was reduced by 'h'
so, put \(\huge x-h\) in place of 'x' in your equation
what do u get ?

Answer 2

(x-h)^3+6(x-h)^2-12(x-h)+32=0

Answer 3

now the 2nd degree term is not present in this
so, put the co-efficient of x^2 =0

Answer 4

i m getting h=-2

Answer 5

how ?
-3hx^2+6x^2 =0

Answer 6

thek hai smjh aa gya mujhe glti kr di thi sign ki sorry

Answer 7

no prob :)

Answer 8

thanks....once again

Answer 9

welcome ^_^