the lengths of the parallel sides of an isosceles trapezoids are 8 in and 16 , respectively. if the diagonal bisects the base angle, what is the area of the trapezoid

Question

anonymous · Answer

we dont know lade

anonymous · Answer

:(

wolf1728 · Answer

I drew a graphic.  Angle A = Angle B

anonymous · Answer

whats the next step?

wolf1728 · Answer

Gee, I don't know - I was hoping someone else would step in.

If nothing else, it seems that the "right side" of the trapezoid could be removed, then rotated into position on the left side, forming a rectangle 12 inches wide.  (Height is unknown).

wolf1728 · Answer

I'm guessing that the diagonal turns the "bottom" of the trapezoid into a 30° 60° 90° triangle.  So the length of the diagonal would be 12* (2/sqrt(3)) = 13.8564064606
and the length of the height would be (hyp/2) = 6.9282032303
So the area of the trapezoid would be 12 * 6.9282032303 = 83.14.