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Algebra 21 Online
OpenStudy (anonymous):

dghkj

OpenStudy (ranga):

Let the number of cars be C and the number of trucks be T. C + T = 32 Cars have 4 wheels and trucks have 6 wheels. 4C + 6T = 148 Can you solve for C and T from here?

OpenStudy (anonymous):

4C + 6T = 148 -4C -4C ___________________ 6T = 148 - 4C

OpenStudy (anonymous):

is that how I would continue?

OpenStudy (anonymous):

I would isolate a variable in the equation C + T = 32 and then sub that back into the other equation

OpenStudy (anonymous):

huuuuuh

OpenStudy (anonymous):

Isolate a variable in C + T = 32. get it to where C = .... or T = ... do you understand ?

OpenStudy (anonymous):

Let me rephrase....get either t by itself or c by itself and everything else on the other side of the equal sign

OpenStudy (anonymous):

Yeah, but how would you figure out C + T

OpenStudy (anonymous):

ok.....what variable do you want to isolate ? You choose, C or T ?

OpenStudy (anonymous):

hello ??

OpenStudy (anonymous):

C?

OpenStudy (anonymous):

C + T = 32 (subtract T from both sides to get C by itself) C + T - T = 32 - T (combine like terms) C = 32 - T do you understand how I did that ?

OpenStudy (anonymous):

yess

OpenStudy (anonymous):

Now we will sub 32 - T in for C in the other equation... 4C + 6T = 148 4(32 - T) + 6T = 148 can you solve for T now or do you need more help ?

OpenStudy (anonymous):

Yeah I think I'm gonna need for help

OpenStudy (anonymous):

4(32 - T) + 6T = 148 -- distribute through the parenthesis 128 - 4T + 6T = 148 -- subtract 128 from both sides -4T + 6T = 148 - 128 -- combine like terms 2T = 20 -- divide by 2 on each side T = 10 now sub 10 in for T in the 1st equation C + T = 32 C + 10 = 32 C = 32 - 10 C = 22 check.. 4C + 6T = 148 4(22) + 6(10) = 148 88 + 60 = 148 148 = 148 (correct) There were 22 cars and 10 trucks any questions ?

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