Question

A hot-air balloonist drops an apple over the side while the balloon is accelerating upward at 4.0 ms^-2 during lift-off. If the speed of the balloon is 2.0 ms^-1 at the moment of release, how long does it take for the apple to reach 200 m below the balloon?

Answer 1

h= ut+1/2 gt ^2

Answer 2

h=200
u=-2
g=9.8

Answer 3

Do I need to consider the displacement of the balloon? Since its going up while the apple's falling.

Answer 4

I think the velocity of apple will b equal to the velocity of baloon

Answer 5

so the velocity of apple will b 2 ms^-1

Answer 6

and it will b upward

Answer 7

ya u can consider the displacement of baloon

Answer 8

So it's displacement of balloon + displacement of apple = 200?

Answer 9

baloon will go upward
but apple will go first upward and then it will go downward

Answer 10

actually the apple will go more than 200 m

Answer 11

Displacement of balloon - Upwards displacement of apple + Downwards displacement of apple = 200?

Answer 12

the displacement of apple will b 200 m

Answer 13

ya right

Answer 14

Like this?
-2t - 2t^2 - (-2t + 4.9t^2) = 200

Answer 15

no

Answer 16

200=-2 t+4.9 t^2

Answer 17

h= ut+(1/2) gt ^2

Answer 18

So t = 6.60 s?

Answer 19

may b

Answer 20

I did not calculate

Answer 21

Thanks

Answer 22

welcome