A 296.9-g brass engine part at an initial temperature of 2.29°C absorbs 93.10 kJ of heat. What is the final temperature of the part? ( The specific heat of brass = 0.380 J g-1 K-1.

Question

joannablackwelder · Answer

Specific heat = q/(mΔT) where q is heat, m is mass, and ΔT is Tfinal-Tinitial.

joannablackwelder · Answer

Because we know it absorbs heat we can check our answer logically. The final temp must be higher than the initial temp.

anonymous · Answer

How do I do this only knowing the initial temp and not the final?

joannablackwelder · Answer

You are solving for the final temp.

joannablackwelder · Answer

Make sure to make your units consistent.

anonymous · Answer

So, .38=93.1/(296.9*??)

joannablackwelder · Answer

?? is (Tf-275.44)

joannablackwelder · Answer

But q= 93,100J to line up units with specific heat value.

anonymous · Answer

whats a ball park figure on what the answer should be?

joannablackwelder · Answer

I got about 1100K

anonymous · Answer

Thank you!

joannablackwelder · Answer

No worries, happy studies!