D to the 4th over d to the 6th the whole thing in parenthesis to the -2 on the outside of the parenthesis ??
do you want to solve or simplify this?
Simplify
do you know what a negative exponent does?
No
ok a negative exponent inverses a problem or flips it upside down
Yea I remember now so it would be d to the 12th over dot the 8th ??
I mean d to the 12th over d to the 8th
yes that is better like that, now simplify!
D to the 6th over d to the 4th
keep going
D to the 3rd over d to the 2nd
errr, I am not following how you got to that answer ... want to explain it :)
Because u simplify d to the 6th to d to the 3rd then d to the 4 is d to the 2
you are simplifying the exponents by pulling out a factor there, but that is not complete ... you need to consider what it may look like without the exponents.
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How would you simplify that?
sorry put one too many Ds up in the numerator!
D to the 2nd
did you come up with an answer once you cross out the extra Ds?
d² you got it!
-2(d^4/d^6) with the divide sign and the same base subtract the exponents -2(d^-2) distribute -2d^-2 put one over all of it due to the - exponent 1/(-2d^2) there's your answer
So pretty much u divided 8 by 4 but then how would u do my problem because they don't go into each other evenly
@zJicez @HANNAH89 check your math again
subtract the exponents from each other.
Oh I see thank you
yep
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Well the 4 is on top and 6 is on bottom
So would the answer be d to the 4th
\[-2(\frac{d ^{4}}{ d ^{6} })\] @zJicez
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