Is the term (x + 2) a factor of the polynomial shown below? f(x)=x^4+5x^3+10x^2+20x+24 A. Yes, the remainder is 48. B. Yes, the remainder is 0. C. No, the remainder is 48. D. No, the remainder is 0.
Do you know how to do synthetic division?
i have an idea, but im not too confident in it. is that what i need to do?
would i do (x^4+5x^3+10x^2+20x+24) divided by (x+2)?
Yes. Then you'll find out if it's a factor, or, if not, what the remainder is. (You can throw out 2 of those choices right away because they aren't logical)
Right. I can walk you through this one if you want.
First write all the coefficients, and the opposite of the divisor. |dw:1383601410387:dw|
okay doing that now :)
Take the first number and just bring it down unchanged|dw:1383601541043:dw|
Now multiply it times your divisor and move that over to the next column.|dw:1383601595724:dw|
Are you following so far?
yes, I completed it and got 1, 3, 4, 12, 0. so does that mean that it would be yes, the remainder is 0 or no, the remainder is 0?
Yes. If the remainder is 0, it's a factor. That's what I meant by two of the options not being logical. It's not a factor if there is a remainder, and if it's a factor, there won't be a remainder.
oh okay, thank you!! :)
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