Question

what are the points of discontinuity on ((x+4)/(x^2-16))

Answer 1

when you simplify the equation, you'll cancel out x+4. That means you'll have a hole at x = -4. so that's one of your discontinuity

Answer 2

and after you canceled out, the simplified equation would be 1/(x-4). but it's undefined at x = 4

Answer 3

also, is the function continuous? no right?

Answer 4

so the point are going to be at x = +- 4

Answer 5

nope.

Answer 6

thank you much you rock

Answer 7

no prob :)

Answer 8

it's not continuous because there is a vertical asymptote at x = 4 and a hole at x = -4