Question

Please Help!!
Which best describes the roots to the equation represented by the graph above?

*two imaginary roots
*one real and one imaginary root
*two distinct real roots
*one real double root

*picture attached*

Answer 1

where's the graph?

Answer 2

@chasitybugg13

graph?

Answer 3

Im trying to load it. It doesnt want to post. Sorry gimme just a sec!

Answer 4

@Easyaspi314 there ya go

Answer 5

Notice that the graph NEVER intersects the x-axis. What can you say about the roots of x?

Answer 6

Let's put it this way...where the graph intersects the x-axis, will be the seros (roots) of the equation.

Answer 7

There isnt gonna be any real roots?

Answer 8

Correct. But it is a quadratic equation (a parabola). So it will have roots, but not real numbers since it doesn't intersect the x-axis. The roots will be imaginary (complex) numbers.

Answer 9

so would it be two imaginary roots?

Answer 10

@chasitybugg13

Does this make perfect sense?

Answer 11

Yes, two imaginary roots.

There cannot be any real roots since the graph never intersects the x-axis.

Answer 12

I'm not gonna lie. I am no good in math so no it doesn't make perfect sense lol. But I get it. Kinda

Answer 13

thank you! Would you mind helping me with a few more?

Answer 14

Watch...let's say we have a graph of y = x^2 - 4.
Lookk at the graph..........

Answer 15

This graph intersects the x-axis at two places, at x = 2 and x = -2. So we say that the roots of the equation x^2 - 4 = 0 are the two real numbers, x = 2 and x = -2.

Answer 16

But in your graph....the equation of that parabola, U-shaped curve, never intersects the x-axis, so it will not have any real number solution.

Answer 17

ohh ok!

Answer 18

Great!

Answer 19

could you help me with 2 more?

Answer 20

Let's take your next question.

Answer 21

Use graphing to find the solutions to the system of equations.
-x^2+y=1
-x+y=2

Answer 22

Let's look at your first equation.

-x^2 + y = 1

If we wanted to graph it, what would be the first thing we want to do?

Answer 23

?

Answer 24

figure out what x and y equal?

Answer 25

yes, we want to solve for y. we always want y = .......

Answer 26

To solve for y, we have to get rid of the -x^2. So what do we do to get rid of the -x^2?

Answer 27

set the equations equal to each other? Maybe

Answer 28

No, to "undo" subtraction, we do addition. So we would add x^2 to both sides.

Answer 29

so on the left side we are left with just y, and the right side we have 1 + x^2. agree?

Answer 30

yes

Answer 31

Agree?

Answer 32

what does y = x^2 + 1.

Well, we know what y = x^2 looks like. It is a U-shaped parabola.

So x^2 + 1, is just taking this U-shaped curve and raising it 1 unit.

Let me show you the graph.

Answer 33

The dotted graph is y = x^2 + 1.

I took the solid graph of y = x^2 and raised it 1 unit upwards.

Answer 34

@chasitybugg13

Do you understand this?

Answer 35

Not really.

Answer 36

Did you ever graph equations y= x^2?

Answer 37

I dont think so

Answer 38

well...I just showed you what y = x^2 looks like.

What level math are you taking?

Answer 39

I'm in Algebra 2 but I'm behind like crazy right now because i have had a lot of stuff going on. and Its midnight and I'm not thinking straight but I have to get my over due assignments done or they are just gonna keep piling up

Answer 40

Maybeyou stop now and return tomorrow evening when you are a bit more rested. It would be important to see how to graph y = x^2...etc.

Answer 41

are you going to be on tomorrow?