Having survived the meteor impact, thanks to some last minute evasive maneuvers, the Mathonauts now set their sights on their Interstellar Headquarters. The Interstellar Headquarters orbits the Earth based on the equation y2 + x2 = 40,000. Using the original trajectory of the ship and complete sentences, explain to the pilot how to find where the ship’s path will cross the Interstellar Headquarters’s path. the original equation is y=6x+2
@Kfins99
you have two equations with y and x you have to use one and plug it into the other to solve the system. since the second equation is in terms of y you should plug this into the other to solve for x
thank you @PhysicsGuru but how would the equation look
instead of \[y^2 + x^2 = 40,000 \] you will plug in 6x+2 for y
try to do some of the steps... you have to factor the term and solve the quadratic equation for x
yeah i tried to do that but it doesnt work cuz of the square i get stuck in the process @PhysicsGuru
ok so we plug in 6x +2 and get \[(6x+2)^2 + x^2 = 40,000\] which can be written as \[(6x+2)(6x+2) + x^2 = 40,000\]
You have to use FOIL for the term on the left
but what about the x^2?
@PhysicsGuru
after everything is on the left side of the equation you have x^2 left
After you foil the term on the left you will add the x^2 afterwards ... always go from more complex to least complex when solving for a variable
tell me how you foil the term on the left
36x^2+12x+12x+4=40000 am i doing it right? @PhysicsGuru
Yes however you are missing the extra x^2 term from the left side of the equation
oh yah so 37^2? @PhysicsGuru
@satellite73 do you think you can help
@ns_69
@goformit100 can you pls helpppp
You have been helped by so many users. Sir How can I hep you ?
i gett lost in the process do you get the problem? i just need you to tell me if im doing it right or not.
@goformit100
. You can substitute your original trajectory (y=5x+1) into the equation that the Interstellar Headquarters is based on (y2+x2=40,000). You will be with the equation 2(5x+1)+x2=40,000 and you will solve for X. After solving for X, you will have X=3333.12 for your value. You will now take this value back into one of your original equations. You will now have the equation y=5(3333.17)+1 and will solve for Y. Your value for Y will be Y=16666.85. You now know the ship’s path will cross the Interstellar Headquarters’ at the coordinate (3333.17, 16666.85).
that doesnt work cuz its to the power and i saw this oh yahoo answers also
ohk that was from yahoo ans fine!
@phi can plzzzzzzz help
\[ y^2 + x^2 = 40,000 \\y=6x+2 \] as already posted up above, replace y in the first equation with 6x+2 \[ (6x+2)^2 + x^2 = 40000 \] can you multiply out (6x+2)(6x+2) ? Did you try ?
yeah i got 37^2+24x+4=40,000
I assume you mean (putting in the x^2) \[ 37x^2+24x+4=40,000 \] subtract 40000 from both sides \[ 37x^2 +24x -39996=0 \] that is a bit ugly looking. But we can use the quadratic formula (with a calculator) to find 2 x values that will work. then you can find the corresponding y values using y= 6x+2 Do you know how to use the quadratic formula?
x=-B+-SQRT b^2-4ac/2a you want me to solve it and tell you?
do it step by step. first what is b^2 - 4ac and the sqr of b^2 - 4ac
ok 24^2-4(37)(-3996)
and we need a number
ok that = -590832?
no, be careful of the signs. minus times minus is plus
ok so 590832?
is your calculator broken ?
lol sorry
wait is it 768.655
type 24^2-4(37)(-3996)= into google. (But I would try to get the same answer using the calculator... you do want to be able to use a calculator... it is a useful thing to know)
I feel like your going to kill me if i dont get this one i swear i typed it as you said but the number is still weird here you go 591984
oops, it should be 24^2-4(37)(-39996)=
ok its 591984
and google says 5919984
that is missing a number. you should get 5,919,984
so thats x?
remember the last number is -39,996 NOT -3,996
so far you found b^2 -4ac = 5,919,984 you now need the square root of that number (and save it because you will need to use a few times)
the sqrt is 2433.101724
ok , now you know \( \sqrt{b^2 -4ac}= 2433.101724 \) now let's find one of the x values x= (-b + 2433.101724)/(2a)
lol ok jst hold up im going to solve this
ok i got 32.5554287
ok,now find y using y = 6x+2
197.3325722
yes, so you have one point where the line intersects the ellipse (32.555, 197.333) (rounded to the nearest thousandth) next, find the other x value, using the minus sqrt(b^2-4ac): x= (-b - 2433.101724)/(2a)
other square you mean x^2 or jst x
(33 ,197)
you lost some minus signs
what minus signs
x= (-b - 2433.101724)/(2a) that will give a negative x. remember the quadratic equation gives two answers because we do ± sqr(b^2-4ac) we are now doing \[ x = (-b - \sqrt{b^2-4ac})/(2a) \]
oh yeah i totaly forgotot so itss (33,197) (-33,-197)
yes. I would round to about 3 decimals, just to show the answer is not an exact integer. (unless the question says round to the nearest integer)
ok Thank you Soooo muchhhhh Phi! i have been stuck on this for quite a while!! :)
Here is a graph of your problem. (I used geogebra, which you can download for free)
Thank YOU!!!!
yw
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