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Algebra 13 Online
OpenStudy (anonymous):

factor: x^2-5x+1=0

OpenStudy (anonymous):

Are you sure that's the right problem? Those factors are going to be ugly. You should probably just find them with the quadratic formula and write the thing as factors. That's what I'd do, anyway.

OpenStudy (anonymous):

Or you can do middle term beaking!

OpenStudy (anonymous):

Breaking*

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

do middle term of 5

OpenStudy (anonymous):

5x

OpenStudy (anonymous):

what does this sign (^) represents? x,square?

OpenStudy (anonymous):

its actually -5x and im so confused I thought we had to find 2 numbers that add up to -5 and when multiplied give you +1??? idk im so lost

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

the sign ^ represents the square root of

OpenStudy (anonymous):

or you can use "complete the square" method

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

Its actually called "completing the "square: divide the coefficient of x by 2 and square it! : x^2-5x+25/4-25/4+1=0 , (x-5/2)^2-21/4=0 , (x-5/2)^2=21/4 , x-5= ±√21/4 , x= 5±√21/4

OpenStudy (anonymous):

thanks I get it

OpenStudy (anonymous):

factors are not always whole numbers! When ur stuck, use the quadratic formular...

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