Find the equation of the linear function f using the given info: f(0)=-3, f(3)=-3 I got a slope of -3, plugged in and got y = x - 3. Is this correct?
How did you get slope = -3?
Somebody told me "since both y values are the same, evidently it is a constant, namely f(x)=−3" and to plug that in
But that's not how you find the slope. You find the slope by using the slope formula: (y2-y1/x2-x1) Do you see where y2, y1, x2, and x1 are? Those are your two sets of coordinates. Use them to find the slope, then you can plug it into the y = mx + b and find b, which will give you everything you need for your equation.
OH, so y = 2x + b and now put in x and y from either set of points
I plugged in 0,0... got 0 = 2(0) + b
What slope did you get? Show me your calculations for slope.
4 - 0 = 4 -2 - 0 = -2 -4/2 = -2/1 which equals -2. My bad
I still get b = 0 regardless, so y = -2x + 0?
Where did you get 4 and 2 from? Your functions are f(0)=-3 and f(3)=-3.
So in the first one, x = 0, y = -3. And in the second one x = 3, y = -3. Those are your y2, x2, y1, x1.
Oh crap I'm sorry, was looking down at my book at the question right below the one I'm going over. it was f(0)=0, f(-2)=4. Well, got that one right now lol.
Doing the right one now
-3 + 3 = 0 3 - 0 = 3 0/3?
So what is your slope? Any fraction with 0 as the numerator equals what?
undefined?
No, that's if there's a 0 in the denominator. 0/3 is a number. A 0 in the numerator of any fraction just makes the fraction equal to 0.
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