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Mathematics 15 Online
OpenStudy (anonymous):

what equation best represented by the graph below ? A. (x+1)(x-3)(x+2) B. (x-1)(x+3)(x+2) C. (x-1)(x-3)(x+2) D. (x+1)(x+3)(x-2)

OpenStudy (anonymous):

OpenStudy (anonymous):

Well for starters on the graph where are our zeros?

OpenStudy (anonymous):

Or another way of saying this when y=0 what does x equal? Hint: y=0 at 3 different points

OpenStudy (anonymous):

im really confused o.O

OpenStudy (anonymous):

Well in order to determine an equation for this graph we have to analyze it Fine the x-axis on the graph or the line where y=0

OpenStudy (anonymous):

OpenStudy (anonymous):

is it in the center of the graph ?

OpenStudy (anonymous):

Look at the image I have attached. The yellow line is the x axis or where y=0 The boxes are the places where the graph touches the x-axis

OpenStudy (anonymous):

so the zeros are -2,1,3

OpenStudy (anonymous):

Yaa :)

OpenStudy (anonymous):

so it would be D?

OpenStudy (anonymous):

Nope and I will explain why

OpenStudy (anonymous):

What are zeros mean is that when we plug in -2,1 or 3 into the equation our y value or our answer must be 0 So lets look at equation D y=(x+1)(x+3)(x-2) Lets plug in 1 (1+1)(1+3)(1-2)=(2)(4)(-1)=-8 Our answer was 6 and not 0 so obviously this aint the answer lets take a look at equation C y=(x-1)(x-3)(x+2) Lets plug in 1 (1-1)(1-3)(1+2)=(0)(-2)(3)=0 Now lets plug in 3 (3-1)(3-3)(3+2)=(2)(0)(5)=0 Now Lets plug in -2 (-2-1)(-2-3)(-2+2)=(-3)(-5)(0)=0 So when we plug in all our zeros the equation does in fact equal 0 If you noticed you will see that basically for the equation to equal 0 the values in each bracket had to be the same value BUT NEGATIVE so since our zeroes are -2,3 and 1 So our equation is (x-1)(x-3)(x+2)

OpenStudy (anonymous):

thank you so much

OpenStudy (anonymous):

I hope you understand it. Its a lil complicating

OpenStudy (anonymous):

But if you dont just know that the values in each bracket must have the opposite sign of the zero

OpenStudy (anonymous):

okay

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