Question

h

Answer 1

no.

Answer 2

He could have just squared them like so...x3^4 = x12
not sure if the last part is correct.(x12)

Answer 3

\[\huge x^3 \times x^3 \times x^3 \times x^3 = x^{3+3+3+3}\]
Peter simplify his work correctly
But compelete final answer is
\[\huge = x^{3+3+3+3} = x^{12}\]

2allie_bear22

Answer 4

@allie_bear22

Answer 5

Wait...i did not know that is was x^3 already...

Answer 6

lol yea it was srry

Answer 7

No, peters work won't be same if he write.
\[\huge x^3×x^3×x^3×x^3 -as-x^3 + x^3 + x^3 + x^3\]
since \[\huge x^3 + x^3 + x^3 + x^3 = 4x^3\]

@allie_bear22