The table below shows the distance d(t) in feet that an object travels in t seconds. t (second) d(t) (feet) 3 126 4 224 5 350 6 504 What is the average rate of change of d(t) between 3 seconds and 5 seconds and what does it represent?
59.5 m/s; it represents the average speed of the object between 3 seconds and 5 seconds 112 m/s; it represents the average speed of the object between 3 seconds and 5 seconds 112 m/s; it represents the average distance traveled by the object between 3 seconds and 5 seconds 59.5 m/s; it represents the average distance traveled by the object between 3 seconds and 5 seconds
Well...\[Average Rate of Change=\frac{ f(b)-f(a) }{ b-a }\]Where f(b) is the y-value for 3 seconds (126), f(a) is the x-value for 3 seconds (3), b is the y-value for 5 seconds (350), and a is the x-value for 5 seconds (5)/
NO! It's the other way around. Sorry! Hold on!
f(b) is 350 and f(a) is 5. b is 126 and a is 3.
Sorry for the confusion.
Anyways, this is your new equation:\[Average Rate of Change=\frac{ 350-5 }{ 126-3 }\]
Solve that and you've got your answer. :)
AND it represents the average speed of the object between 3 seconds and 5 seconds.
345/123?
Yep. :) Simplify now.
2.8!
Hm.
oh simplify i divided lol...
No, thats the same thing.
oh ok...
Wow. Hm....
OH!
I think I'VE GOT IT.
\[Average Rate of Change=\frac{ 350-126 }{ 5-3 }\]
ahhhh!!!
112!
Okay, there's your answer. Lol.
Sorry for the confusion.
np!
so wait is it b?
@kewlgeek555 please help...
Yes, I believe it's B.
k thanks! neeed any help with anything?
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