Question

Solve for b.
\frac{ 1 }{ b-5 }-\frac{ 10 }{ b^2-5b+25 }=\frac{ 1 }{ b+5 }

Answer 1

\[\frac{ 1 }{ b-5 }-\frac{ 10 }{ b^2-5b+25 }=\frac{ 1 }{ b+5 } \]

Answer 2

find a common denominator and multiply both sides

Answer 3

i dont know how

Answer 4

@Luigi0210
could you explain how can i solve this equation
solve for b
\[\frac{ 1 }{ b-5 }-\frac{ 10 }{ b^2-5b+25 }=\frac{ 1 }{ b+5 } \]

Answer 5

Do what Bunki suggested

Answer 6

i cant simplify b^-5b+25

Answer 7

pffft easy

Answer 8

>.>

Answer 9

Factor the middle fraction. You should see some similarities, then you should see how something will cancel.

Answer 10

Aaaaaaand, he left the question.......

Answer 11

i dont know how to factor it

Answer 12

b^2-5b+25=( ?)(? )

Answer 13

All you luilui, I have to go now. Good luck andrijano :)

Answer 14

i spend so much time in this question,im not geting anywhere ,

Answer 15

i cant figure out what
d^2-5b+25=(?)(?)

Answer 16

well,what do i do now?

Answer 17

Try to clear the fractions.

Answer 18

multiply both sides by (b-5)(b+5)(b^2-5b+25)

Answer 19

\[\frac{1(b-5)(b+5)(b^2-5b+25)}{b-5}-\frac{10(b-5)(b+5)(b^2-5b+25)}{(b^2-5b+25)}=\frac{1(b-5)(b+5)(b^2-5b+25}{b+5}\]

Answer 20

it was too long
but just multiply both sides by (b-5)(b+5)(b^2-5b+25) to clear the fractions.