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Mathematics 15 Online
OpenStudy (anonymous):

Derivative of Exp[Abs[x]]?

zepdrix (zepdrix):

So we need to find this derivative?\[\Large \left(e^{|x|}\right)'\]

OpenStudy (anonymous):

yes

zepdrix (zepdrix):

Hmm I guess we would follow the normal rule for derivative of an exponential and then follow it up with the chain rule.\[\Large \left(e^{|x|}\right)'\quad=\quad e^{|x|}\color{royalblue}{\left(|x|\right)'}\]

OpenStudy (anonymous):

(d/dx) (Abs[x]) =+-1?

OpenStudy (anonymous):

depending on x?

zepdrix (zepdrix):

\[\Large \frac{d}{dx}|x|\quad=\quad \frac{d}{dx}\sqrt{x^2}\quad=\quad \frac{x}{\sqrt{x^2}}\quad=\quad \frac{x}{|x|}\]

zepdrix (zepdrix):

But ya if we write out specific intervals of x, we could get rid of the absolute bars. That might look a little better.

OpenStudy (anonymous):

is by definition Abs[x] = Sqrt[x^2]?

zepdrix (zepdrix):

Ya, that's a good one to remember probably c:

OpenStudy (anonymous):

thank you, you have been very helpful! have nice day!

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