sec sin^-1(- 1/4) use a sketch to find the cxact value of the follwing expression. help plesssssss
i need to know the correct formula for the function can u repeat it ?
I dont know what formula I have to use
i ment the qs this is "sec sin^-1(- 1/4)" right ??
correct
??
ok u can write it like this y=sec sin^-1(- 1/4) = sec (1/sin (-1/4) now since there is no such variable x.. its constant function . need to now sin(-1/4)=-0.247 "from calculater" so y= sec(1/-0.247)=-1.623 "from calculater" now u have y=-1.623 drow it
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so what do u think the answer is ?
lol its "-1.623 " but there is another way to get the answer ready ??
cause I have to write only the final answer that is all what they need
For the sin of an angle to be 1/4, that means the opposite side is 1, and the hypotenuse is 4 so the adjacent side is √(4² - 1² ) = √(15) that means the cosine is √(15)/4 so the secant is ± 4/√(15), depending on if the angle is in Q3 or Q4
is that right or wrong ?
yes its the ansewr , although i think the qs a bet waired usually its written like this sec (- 1/4) sin^-1(- 1/4) thats y a asked u first a bout the formula if its correct
it is sec(sin-1/4
ok now i got u sin^-1 means the invers fun not 1/sin .
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okay ?
its negative
well the sin is allways positive on first & second quarter so sin(-1/4)=sin(1/4)
oh okay , so the answer is !!
huh , u typed it lol !!! i was checking my knowlege.
I have 10 more minuts I realy need the right final answer ples
i told u , that u got it , but its positive \[4/\sqrt{15}\]
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