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Mathematics 13 Online
OpenStudy (anonymous):

~Medal+Fanning~ Select the system of equations that corresponds to the given graph. 4x + 2y = 12 4x + 2y = 4 2x + 3y = 4 6x + 9y = 12 2x + 4y = 12 2x + y = 3 2x + 3y = 8 −x + y = −4

OpenStudy (anonymous):

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

It looks as if the two equations in the systems of the answer options combine to be just one line. That is, there is only one line shown in the posted graph.

Directrix (directrix):

@HelloGoodmorning What do you think could or would cause that?

OpenStudy (anonymous):

I'm not the best at these I only know know that it being on the same line is infinitely many solutions @Directrix

Directrix (directrix):

Hey, that's a big clue. When two different lines intersect, they intersect in a single point. That is one solution. If you have infinitely many solutions, the two line equations are the same but just look different at first glance.

Directrix (directrix):

So, look at the answer options and see if any two of the equations in an option are really the same equation in disguise. I'll do an example to show you what I mean by that.

OpenStudy (anonymous):

Okay!

Directrix (directrix):

I am starting with option D. 2x + 3y = 8 −x + y = −4 These look as if the second equation might have been multiplied by 2 to get the first one. Let's check.

OpenStudy (anonymous):

Okay.

Directrix (directrix):

2x + 3y = 8 --> --> 2x + 3y = 8 −x + y = −4 --> Multiply by 2 --> -2x + 2y = -8 @HelloGoodmorning Are these two equations identical in every number.

OpenStudy (anonymous):

No

Directrix (directrix):

Right. So, look at option C. Do those equations look like they could be made to be identical in every number?

OpenStudy (anonymous):

Let me check

Directrix (directrix):

We're looking at these: 2x + 4y = 12 2x + y = 3

OpenStudy (anonymous):

Ok question How do I know if they're in disguise

OpenStudy (anonymous):

@Directrix

Directrix (directrix):

Can you make one look like the other? Multiply the second equation by 2 and see if it becomes the first equation. 2x + 4y = 12 2x + y = 3

OpenStudy (anonymous):

No.

Directrix (directrix):

Correct. They both had 2x in them so when you try to get the y terms and constant terms to be the same, the x terms are changed. Now, we go to option B.

Directrix (directrix):

2x + 3y = 4---> Multiply by 3 ---> ? @HelloGoodmorning 6x + 9y = 12

OpenStudy (anonymous):

Okay and we multiply it by 2

OpenStudy (anonymous):

Oh okay 3

Directrix (directrix):

3

OpenStudy (anonymous):

Hey! It looks like b is it

Directrix (directrix):

Yes! Hey, I want you to see what happens when these are graphed. Just a second.

OpenStudy (anonymous):

Okay sure thing!

Directrix (directrix):

Click on this link: http://www.wolframalpha.com/input/?i=+2x+%2B+3y+%3D+4%2C+6x+%2B+9y+%3D+12+

Directrix (directrix):

That is the graph of the two equations from option B. We could have entered the equations of all the options to see which one produced the graph you were given in the problem. But, we used a better approach, I think.

OpenStudy (anonymous):

Wow good website and that's okay you taught it very well and also I gave you a testimonial earlier because you always help me!

Directrix (directrix):

Yes, I saw that. Thank you very much. It means a lot to me.

OpenStudy (anonymous):

No Problem :) Thanks for helping again.

Directrix (directrix):

You are welcome.

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