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Mathematics 50 Online
OpenStudy (anonymous):

Sec sin^-1(- 1/4)

OpenStudy (agent0smith):

Ignore the sec for now. Use this, let the inverse sine equal to theta \[\Large \sin^{-1}(- 1/4) = \theta \] so now \[\Large \sin \theta = -1/4\]follow?

OpenStudy (anonymous):

yeah

OpenStudy (agent0smith):

Okay now make a triangle using that... |dw:1383693310255:dw|

OpenStudy (anonymous):

yeah

OpenStudy (agent0smith):

Find x.

OpenStudy (agent0smith):

remember we had Sec sin^-1(- 1/4) we let θ equal the sin^-1(- 1/4) part, so we have secθ now

OpenStudy (agent0smith):

Also keep in mind sin θ = -1/4... which means theta must be in the 3rd or 4th quadrant (where sine is negative)

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