Determine Types of Lines:(Parallel, Perpendicular or Oblique)
-2x + 9y =19 -18x - 8y = 7
may anyone help me pleasseeee
First rewrite each equation in slope-intercept form. Slope intercept form is: y = mx + b
idk how to well i did learn that a loooooong time ago and i forgot to do that
I will do the first one you do the second. -2x + 9y =19 We need to isolate y on the left hand side. Add 2x to both sides: 9y = 2x + 19 Divide each term by 9: y = 2/9x + 19/9 That is slope-intercept form. The slope if the coefficient of x. Here the slope = 2/9 You do the second.
-18x - 8y = 7 -8y-18x=7 y=26 i dont know if im doing it right i dont feel so confident about this
-8y - 18x = 7 We need to isolate y on the left hand side. What other term is there on the left side besides -8y and what should we add to the left to get rid of it?
there is -18x so u add 8y so get rid of y and to find the x?
No we want to keep y on the left. We want o get rid of the -18x. The way to do that is to add 18x to both sides: -8y - 18x = 7 + 18x +18x -8y = 18x + 7 We want only y on the left. So divide both sides by -8: y = -18/8x - 7/8 y = -9/4x - 7/8 This is the slope-intercept form of the second line. The slope is coefficient of x term. It is -9/4 So slope of the first line = 2/9 and slope of the second line = -9/4 For two lines to be parallel, their slopes must be the same. Here the slopes are different and therefore the lines are not parallel. For two lines to be perpendicular, the product of their slopes must be -1. Here the product of the slopes is (2/9)(-9/4) = -1/2 which is not -1 and therefore the lines are not perpendicular. Therefore the lines must be oblique.
thank you very much
you are welcome.
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