Question

Closed.

Answer 1

\[\sqrt[3]{x ^{2}}\times \sqrt[3]{x ^{2}}\]

Answer 2

\[\Large \sqrt[n]{x^m} = x^\frac{ m }{ n} \quad \]

Answer 3

\[\Large x^m * x^n = x^{(n+m)}\]

Answer 4

\[x ^{\frac{2}{3}}\times x ^{\frac{2}{3}}\]

Answer 5

So, would the answer be \[\sqrt[3]{x}\]

Answer 6

You need to add the exponents: x^(2/3) * x^(2/3) = x^(2/3 + 2/3) = ?

Answer 7

So, it'd be x^4/6, but you have to simplify, so x^2/3

Answer 8

2/3 + 2/3 is not 4/6

Answer 9

Oh woops! 4/3

Answer 10

Yes. x^(4/3) which can be put back in the radical form as:\[\Large \sqrt[3]{x^4}\]

Answer 11

a.\[x \sqrt[3]{x}\]
b. \[\sqrt[3]{x}\]
c. x
d. \[x ^{\frac{ 4 }{ 9 }}\]

Answer 12

I'm confused, because those are my options.

Answer 13

\[\Large \sqrt[3]{x^4} = \sqrt[3]{x^3 * x} = \sqrt[3]{x^3} * \sqrt[3]{x} = x * \sqrt[3]{x}\]

Answer 14

Oh! I see! Thank you!

Answer 15

you are welcome.