A box with a square base and open top must have a volume of 4,000 cm3. Find the dimensions of the box that minimize the amount of material used.
V = 4,000 = x^2 (h), where x is the one side of the base, h is the height and V is the volume S = x^2 + 4(x)(h), where S is the surface area. h = 4,000/(x^2) S = x^2 + 16,000(1/x) differentiate S with respect to x dS/dx = 2x - 16,000/x^2 = 0 since dS/dx = 0 is a minimum 2x^3 - 16,000 = 0 x^3 = 8,000, x = 20 The sides are 20 cm, and the height is 10 cm
Does that help?
why did you set the derivative of S = 0
idk yahoo lol
hahaha. well thanks anyway lol. the answer came up as correct. I'll try and figure out what was done lol
lol no problem , good luck with the rest.
thank you!
your welcome!
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