if the points (3,r) and (r,-1) lie on a line with slope (-3/4) what is the value of r?
okay so we have got 2 points... Let's call them A and B. where A(3,r) and B(r,-1).
we want to find the value of r, so let's tke those points and find the equation of the line that goes through those points.
We have the slope, so it would be optimal to do this exercise with the point-slope formula and taking arbitrary A or B. Do you follow?
I understand all except the last response, can you explain what arbitrary means?
arbitrary means basically "any you want" so you can choose any of those points to apply the point-slope formula.
so where would we go from there?
Now, we have two points, i'll pick point A(3,r) and use the point slope formula: \[y-y _{1}=m(x-x_{1})\] where m is the slope and x1, y1 the point's coordinates. I'll use that for A(3,r), ending up with: \[y-r=-\frac{ 3 }{ 4 }(x-3)\] I'll apply distributive to get rid if the -3/4: \[y-r=-\frac{ 3x }{ 4 }+\frac{ 9 }{ 4 }\] continuing let's add "r" to both sides and use common denominator: \[y=\frac{ -3x+9+4r }{ 4 }\] multiplying both sides by 4 we get: \[4y=-3x+9+4r\] So now we found an equation that can help us find r, and we know that point B belongs to this line, so we can replace x and y with the coordinates of B: \[-4=-3r+9+4r\] operating a little, we get: \[(4-3)r=9-4\] and our final answer is: \[r=5\] Not hard, was it. Now try doing it but picking B first.
That makes sense, thank you! but I don't think i did point b right r+1=(-3/4)(3-r) r+1=-9/4-3/4r 1/4r=-13/4 r=-13
oh, you have to write the point-slope equation for just one point, simplify and then replace the values of the points.
so is the value of r 5 or -13?
5 right? i think i see where i went wrong
yeah i set the equation up wrong, thank you so much!!!
No problem, I love helping people.
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