Graphing Square Root Functions need help
Okay, show me the functions.
okay, let's find the domain of that function, by domain, I mean the values that it can't take.
Domain: \(6x + 42 \ge 0\) Can't be negative under there, can it?
yes, it can, since it's a cubic root.
\[\sqrt[3]{-27}=-3\] It's perfectly cool that the funtion reaches the negative values.
it can also be 0, remember that the sqrt of 0 is 0, and so, by any index it'll still be 0 so we can say that the domain is any real number.
Am I now understanding the problem?... Is the function a cubic root?
You must clarify. Is it \(this\;3\sqrt{6x+42}\;or\;this\;\sqrt[3]{6x+42}\)?
There you go. Then solve \(6x+42 \ge 0\), and you'll be done.
No, "-7" is just a number. You require an equation that expresses a subset of the Real Numbers. \(x \ge -7\)
First, you must WRITE what you mean. Words mean things. Second, that other problem is quite silly-looking and unnecessarily complicated. Are you SURE you have it right as you have written it? Third, if you have it right, you show me, using the exact same logic and procedure, how to find the Domain.
So, again, all you have is an expression. Do you mean: \(y = 2\sqrt{3x+4} - 5\)? The "y=" part is not optional if you intend to define a function or relation.
What's the Domain of y = x?
?? What makes it not defined? That is free and open. The Domain of y = x is All Real Numbers. There is no number that is inappropriate to be used for x. x = 1? Yes. Perfectly fine. x = 2? Yes. Perfectly fine. x = -12? Yes. Perfectly fine. x = 3 billion. Yes. Perfectly fine. We had trouble before because of the square root. With y = \sqrt(x) x = 1? Yes. Perfectly fine. x = 2? Yes. Perfectly fine. x = -12? No, that just won't do at all. x = 3 billion. Yes. Perfectly fine. y = x Domain: All Real Numbers. You must believe this.
ok, thanks for letting me know that. I appreciate you help on the last problem. I will just go to tutoring tomorrow. Thanks anyway
?? As you wish.
I thank you for your help. It seems like you know your math. Some of us struggle with it. I didn't seem like you wanted to help me. It seems like you were trying to be rude.
I didn't just want the answer, but I would like to see how you got the answer. I don't need a whole history lesson in Algebra though.
This is a consistent problem when working with volunteers. The one seeking assistance thinks there is a need to control the experience. The one seeking the assistance somehow believe he/she is qualified prescribe the teaching methods that will be most helpful. This is all quite contrary to the truth. If you want to control it, you should consider paying for it. If you seek assistance, you should consider trusting those from whom you seek it. When you present a question to a volunteer, a volunteer who is here ONLY because he/she wants to be helpful, you should take a moment to realize that the volunteer's time is quite valuable. If a volunteer takes the time to give you a "history lesson in algebra", it is because he/she feels it is what you are missing that will help you past the difficulties you are experiencing. There is no magic wand for understanding mathematics. It is often a struggle similar to a foreign language. It takes time and requires increasing familiarity as you go along. Background information often provides what is needed to get past certain difficulties. It is a fact of the teaching of mathematics that exactness, thoroughness, neatness, and care benefit the student and encourage or facilitate learning. Sloppiness, carelessness, and casualness harm the student and prevent learning. If you continue to believe that teaching care and consistency constitutes an unnecessary history lesson, you will continue to struggle with mathematics. It is also a sad reality that honesty and clarity often are mistaken for rudeness or self-aggrandizement. I do not know how to solve this social problem. I truly cannot count the times I have told a student the truth, perhaps , "You cannot do this without a better background in ____________", and the student DECIDES this honest and truthful comment is rude or insulting. It's just the truth. There is no necessary value judgment attached to it. Well, that's more than I intended to say, but there it is.
Ok!!!!!!
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