x^4-16^2 find the x intercepts are they 4 and -4 only or is there a 0 intercept

Question

anonymous · Answer

To find x-intercepts, let y = 0, and solve for x.

So you have 0 = x^4 - 16x^2.

Can you solve for all x?

anonymous · Answer

no it would be 0=0 right

anonymous · Answer

so just 4 and -4 then

anonymous · Answer

@normman1978 

Can you show me your work how you solved?

anonymous · Answer

@normman1978 

I would like to see your work.

anonymous · Answer

ok my mistake its x^4-16^2=0  x^4=16^2    x^4=256   x=4,-4

anonymous · Answer

@normman1978 

You haven't shown me how you solved the equation.

If you dont know, tell me...so I can help.

We are here to learn.

anonymous · Answer

|dw:1383712268207:dw|

anonymous · Answer

was that not right

anonymous · Answer

It hits 0 twice.

anonymous · Answer

@normman1978 

I wanted to see an algebraic solution to the equation.

Apparently, you are not responding.

anonymous · Answer

What I did is called synthetic division

anonymous · Answer

can you not see my answers

anonymous · Answer

$$ x^4-16^2=0  x^4=16^2    x^4=256   x=4,-4$$

anonymous · Answer

@normman1978 

I am not interested in your answers if you dont show me your work ...as to how you solved the equation.

If you don't want to show me, that is your choice. I just offer to help.

Good luck.

anonymous · Answer

What are you talking about   u said have y = 0 and i did  $$x^4 -16^2 = 0$$

anonymous · Answer

$$x^4=-16^2$$

anonymous · Answer

$$x^4=256$$

anonymous · Answer

$$\sqrt[4]{x}=\sqrt[4]{256}$$