whats square root 20v^6??

Question

whats  square root 20v^6??

tkhunny · Answer

$\sqrt{20v^{6}}$

Find the perfect squares

$\sqrt{5\cdot 4\cdot v^{6}}$

Attack them one at a time.

$\sqrt{5}\sqrt{4}\sqrt{v^{6}} = \sqrt{5}\cdot 2\cdot \left|v^{3}\right|$

anonymous · Answer

So the answer is $$\sqrt{5}$$*2*|v^3| ?

anonymous · Answer

$$\sqrt{5}\times2timesv ^{3}$$

tkhunny · Answer

Absolute Value of v^3.

anonymous · Answer

wait so whats the answer? hah sorry D:

tkhunny · Answer

I already wrote it up above.  Now, let's see you do one.  Only one for free.

anonymous · Answer

But your answer doesn't work...

tkhunny · Answer

The answer is correct as I have stated it.  However, someone may have overlooked the absolute values.  Try it without them.  It will be wrong, but it may take it.

Next time, let's try YOUR answer and see if it works.

anonymous · Answer

it says assuming v represents a positive real number

anonymous · Answer

i got √5√4 but didnt know what to do with v^6

tkhunny · Answer

Very good.  That is wonderful information.  You did not provide it, before.  This makes all the difference.  Now, we have $2v^{3}\sqrt{5}$.

Please provide the ENTIRE problem statement and please provide your best work.

tkhunny · Answer

If v > 0, we have $\sqrt{v^{6}} = [v^{6}]^{1/2} = v^{6\cdot (1/2)} = v^{3}$

anonymous · Answer

Okay since v^6 reduces to v^3, then its just 2v^3√5

tkhunny · Answer

You tell me.  You're the one who has the software that thinks it knows stuff.  Did we get what it wants, or not?

It is very important to note that "v^{6} reduces to v^3" ONLY because we know v > 0.

anonymous · Answer

yes! that one worked. thank you!!