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hey guys help me :D wuts the integral of \[e ^{-x ^{2}}\]?
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i got \[e ^{-x ^{2}}(-2x)\] but i don't think that's right...
No, it requires the error function. It is \(\frac 1 2 \pi^{1/2} erf(x)\).
wait wuts the error function? and how come the integration rules don't apply here????
lol can't go on youtube right now :P
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doesn't it significantly change the integral value?
Yes. It's essentially \(\sqrt \pi\).
ok so lemme tell u the whole problem. im trying to find the area under the curve in the interval (0,0.922) for the function i posted, and im getting a negative value...the sq rt pi won't change the sign...the graph is above the x-axis so im suppose to get a positive value...
It's positive.
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