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Does Sin(ln(x))/sqrt(e^x+5) have a absolute min on 1
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Start off by looking for the function's critical points. When is its derivative zero or undefined? \[f(x)=\frac{\sin\ln x}{\sqrt{e^x+5}}~~\Rightarrow~~f'(x)=\frac{\dfrac{\sqrt{e^x+5}}{x}\cos\ln x-\dfrac{e^x\sin\ln x}{2\sqrt{e^x+5}}}{e^x+5}\] \[\frac{\dfrac{\sqrt{e^x+5}}{x}\cos\ln x-\dfrac{e^x\sin\ln x}{2\sqrt{e^x+5}}}{e^x+5}=\frac{\dfrac{1}{x}\cos\ln x-\dfrac{e^x\sin\ln x}{2(e^x+5)}}{\sqrt{e^x+5}}\] Clearly, \(f'\) is undefined for \(x\le0\). Now, given such an intricate function, it's not inconceivable to think you can use a graphing utility to find the critical points.
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