Question

The sum of two numbers is 18. the sum of their square is four more than 16 times the larger number. What is the number?

Answer 1

How do I solve this using only one variable?

Answer 2

Let the greater number be x
Let he smaller number be y Needd to use 2 variables

Answer 3

Form an equation of this first The sum of two numbers is 18.

Answer 4

form two equations asume numbers r x & y
x+y =18 ..... assume x is the larger , y=18-x
second equation x^2+y^2+4=16x

Answer 5

Then what would i do next? transpose 16x?

Answer 6

so now substitute y value in the second equatoin
\[x^2+(18-x)^2+4=16x\]

Answer 7

analyzed between brackets
\[x^2+(324+x^2-36x)+4=16x\]
transpose 16x
\[2x^2 -52x+328=0\]

Answer 8

solve for x in the finall equation .

Answer 9

x1= 10 and x2=16

Answer 10

@ikram002p is this correct?

Answer 11

but sry i made a mistake the second equation is
x^2+(18-x)^2-4= 16 x
so the equation would be
x^2 - 26x+160=0
So ur answer is correct good job.

Answer 12

But the sum of those numbers he found he not 18.

Answer 13

you also need to find y

Answer 14

guess the number they are looking for is the larger number anyways

Answer 15

yeb he found 2 values for x now find 2 values for y
x+y=18

Answer 16

Ok. Thanks for the help!

Answer 17

ur wlc :) u such a smart one

Answer 18

thanks