What is the mass (in grams) of 9.66*10 to the 24 molecules on methanol (CH3OH)
use these 2 equations: \(n=\dfrac{N}{N_A}\) ; n=moles, N=number of particles, \(N_A\) =avogadros number and \(n=\dfrac{m}{M}\) ; n=moles, M=molar mass (in g/mol), m=mass (in g)
@aaronq but i dont know how i would set it up. i keep getting the wrong answer?
can you plz help me solve it
okay, in the first equation, you're looking for moles \(n=\dfrac{9.66*10^{24}}{6.022*10^{23}}\) then in the second equation you're looking for mass: \(n=\dfrac{9.66*10^{24}}{6.022*10^{23}}=\dfrac{m}{M_{methanol}}\) so look up the molar mass of methanol and solve for m
im looking for it but im lost i cant find it:( @aaronq
use the periodic table (you have to add the mass of the individual atoms), CH3OH is not an element
okay so c its 12.01+1.01+16.00+1.01=30.03 so m = 30.03 is that correct
@aaronq
there are 4 hydrogens not 2
12.01+(3)1.01+16.00+1.01
@aaronq 32.05
then wats the next step or thats the answer
use the equation i wrote previously
yeah but can you help me solve cuz i dont have a calculator and i dont know how plz
@aaronq
plug it into where molar mass goes and solve for m
k i try
@aaronq i cant:( it i cant do it can you solve it for me plz
why can't you? show me what you did
because in the example idk where 32.05 goes? so i divided by wat?
M= molar mass \(M_{methanol}= 32.05\;g/mol\)
so 32.05 g thats the answer? because i try it nad it was wrong?
@aaronq
dude, use a calculator. I'm willing to help you but not do it for you.
aww u wont why?
:(
@abbieWhat is the mass (in grams) of 9.66*10 to the 24 molecules on methanol (CH3OH)
can u help me plz @abbie
I'm not good at this but here's an example I found Divide 3.62x10^24 by 6.01 x 10^23 (Avogadro) Then you find about 6 mol methanol. The molar mass is (12 + 3 + 16 + 1) gram. you add them and get an answer.
work on it and tell me what you get
@abbie yeah i did that and got 32.05 but it was it in grams
im stuck
@amistre64 can you help him?
@abbie what about this one how many atoms are in 187 g of calcium? _______atoms
how much does one molecule of the stuff weigh?
if m is equal to the mass of 1 molecule then: m * 9.66 * 10^(24), is the mass they are looking for right?
YES
i got that part i added the mass by individual and got 32.05 but then what??
because i added C,H,O,H
\(\dfrac{9.66∗10^{24}}{6.022∗10^{23}}=\dfrac{m}{32.05 g/mol}\rightarrow m=\dfrac{32.05 g/mol*9.66∗10^{24}molecules}{6.022∗10^{23}molecules/mol}\)
so divided that or wat?] nad i got 5.32
g
@abbie how many atoms are in 187 g of calcium can u help do this one plz?
you need to work on your algebra.
i know and i got it wrong i havent had math is years thats why?
can u help me solve it @aaronq
you simply need to plug it into your calculator, it's 514.119893 g
thanks . i have another question convert 0.108 mol of lithium to grams? ___g
use \(n=\dfrac{m}{M}\)
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