Question

a voltmeter has resistance of 2000ohms and it can measure upto 2V. if we want to increase its range to 10V then required resistance in seriese will be
2000 ohm
4000ohm
6000 ohm
8000 ohm

Answer 1

@AllTehMaffs

Answer 2

How please explain it ?

Answer 3

I think it's 8000Ω, but I'm not sure.

If the maximum reading of the voltmeter is 2V at 2000Ω, then the current running through it would be

\[ 2V = I \ (2000 \Omega)\]
\[I = .001A\]

The current should stay the same, so to increase the max reading of the voltage to 10V by connecting a resistor in series would be

\[10V = (.001A)(2000 \Omega + R)\]
\[R = 8000 \Omega\]

I've never done a problem like this this, however; basing that all on these problems/answers

http://en.docsity.com/answers/240648/galvanometer-resistance-deflection-voltmeter-resistance

#10) http://webcache.googleusercontent.com/search?q=cache:ccFg31dihokJ:http://ckw.phys.ncku.edu.tw/public/pub/Notes/GeneralPhysics/Solutions/2012S/H-ElectricCircuit-Solutions.doc%2Ba+certain+voltmeter+has+an+internal+resistance+of+10000&oe=utf-8&rls=org.mozilla%3Aen-US%3Aofficial&client=firefox-a&hl=en&ct=clnk

Answer 4

^_^

Answer 5

thank you :)

Answer 6

welcome ^_^ Did you see that the fridge problem got solved?

Answer 7

Oh I check it .Thank you so much :)

Answer 8

Lessis solved it ^_^