how many atoms are in 187 g of calcium? can someone help me pls
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OpenStudy (aaronq):
use the formulas i showed you before,
\(moles=\dfrac{mass}{molar\;mass}\) and \(moles=\dfrac{particles}{avogadros\;number}\)
OpenStudy (anonymous):
187/12.01 right
OpenStudy (abb0t):
Where did you get 12.01??
OpenStudy (abb0t):
That's not the molar mass for calcium
OpenStudy (anonymous):
idk i dont know how to it? can u help do it plz
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OpenStudy (anonymous):
i want how many atoms are in 187 g of calcium
OpenStudy (abb0t):
Follow what the person above me first told you. Divide the mass given by the \(\sf \color{red}{molar~mass}\) of calcium. Then by avogadro's number, which is: \(\sf \color{blue}{6.022 \times 10^{23} \frac{atoms}{mol}}\)
OpenStudy (abb0t):
The molar mass can be found by looking at your periodic table, where it says "Ca" for calcium.
OpenStudy (anonymous):
so thats the answer
OpenStudy (abb0t):
No, that's not the answer. You have to solve for it. I gave you the steps
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OpenStudy (anonymous):
the calcium is 40.08
OpenStudy (gtxmuqsit):
@emanuelfarias sory I see your qts now wait for 3 minutes
OpenStudy (gtxmuqsit):
\[2.0809x10^{24}\]
OpenStudy (anonymous):
@GTXMUQSIT okay just need this question how many atoms are in 187 g of calcium?
OpenStudy (gtxmuqsit):
2.0809x10 to the power 24 atoms
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OpenStudy (gtxmuqsit):
@emanuelfarias
OpenStudy (anonymous):
its wrong:(
OpenStudy (gtxmuqsit):
why?
OpenStudy (anonymous):
@GTXMUQSIT
OpenStudy (anonymous):
IDK
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OpenStudy (gtxmuqsit):
what's the anwer then? @emanuelfarias
OpenStudy (gtxmuqsit):
answer
OpenStudy (anonymous):
i have 5 min to finish it idk
is not telling me omg
OpenStudy (anonymous):
okay so we need 187g of calcium to atoms right
OpenStudy (gtxmuqsit):
there are 2 ways to write the answer first I told ya second 20.809x10 to the power 23
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OpenStudy (gtxmuqsit):
yeah first divide given mass with molar mass then multiply it with avagadro's no.
OpenStudy (anonymous):
nope it didint work
OpenStudy (anonymous):
idk but with the first u say 2.0809 is not 20.809
OpenStudy (gtxmuqsit):
@emanuelfarias buddy \[2.0809*10^{24}\]
OpenStudy (gtxmuqsit):
\[20.089*10^{23}\]
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OpenStudy (gtxmuqsit):
both same thing
OpenStudy (gtxmuqsit):
@emanuelfarias
OpenStudy (abb0t):
Follow my instructions. Don't give direct answers.
OpenStudy (gtxmuqsit):
20.809x10 to the power 23 and 2.809x10 to the power 24 both are same in term of scientific notation just see decimal @emanuelfarias
OpenStudy (gtxmuqsit):
@abb0t I have proved him above how to solve
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OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
@GTXMUQSIT Thanks alot u were alot of help u r the best:) thank u again im going off to class
OpenStudy (gtxmuqsit):
@emanuelfarias ok welcome
OpenStudy (anonymous):
@GTXMUQSIT HEllo
OpenStudy (gtxmuqsit):
@emanuelfarias how are you?
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