Question

Can anyone help me with this Matrices question? Cramer's Rule we are using also.

Answer 1

\[ A=\left( \begin{array}{cc}
a & b \\
c & d \\
\end{array} \right)\]
\(|A|=ad-bc\)

Think you can take it from there?

Answer 2

Well I have an issue with multiplying Fractions :/

Answer 3

\[2\pi*\frac{ 1}{ 2 }- \frac{ 1 }{ 8 }*4\]

Answer 4

Think of it like this,

\(\displaystyle\frac{a}{b}\times\frac{c}{d}=\frac{a\times c}{b\times d}=\frac{ac}{ad}\)

\(\displaystyle \frac{2\pi}{1}\times\frac{1}{2}=\frac{2\pi\times1}{2\times1}=\frac{\cancel{2}\pi}{\cancel{2}}=\pi\)

You multiply the top terms, and you multiply the bottom terms.

Does all of this make sense?

Answer 5

\[1-\pi/2\] is what is left then

Answer 6

no \[\pi/2\]

Answer 7

since it canceled out

Answer 8

Where exactly are you getting these numbers? :/

Answer 9

when you multiply everything else out \[4*1/8= .5 and 2\pi*1/2\]

Answer 10

No, that is subtraction silly :P not another multiplication :D

Answer 11

._. *flips table*

Answer 12

God I hate matrices

Answer 13

It is fine, you had it correct up above.

\((2π\times\frac{1}{2})−(\frac{1}{8}\times4)\)

What would this be?

Answer 14

\[\pi-1/2?\]

Answer 15

Indeed :D

Answer 16

O: Thank you

Answer 17

You are very welcome!