Question

ln ((1)/(3x^5))

Answer 1

whats the question?

Answer 2

derivative

Answer 3

Best approach is to first simplify that expression:

Using Law of logs: ln (a/b) = ln a - ln b

So, ln(1/(3x^5)) = ln 1 - ln (3x^5)
Since ln 1 = 0, the expression is just - ln(3x^5).

Now you want to find the derivative of -ln(3x^5)

Use the formula that the derivative of ln(u) = 1/u du

You can take it from here?