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Mathematics 22 Online
undeadknight26 (undeadknight26):

Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown.

undeadknight26 (undeadknight26):

undeadknight26 (undeadknight26):

y = 2/5x + 1 y = -5/2x - 23/2 y = -2/5x - 3 y = 5/2x + 23/2

undeadknight26 (undeadknight26):

@SolomonZelman

undeadknight26 (undeadknight26):

@ehuman @amistre64 @charlotte123 @Loser66

undeadknight26 (undeadknight26):

Lol what happened to all the posts!!!

OpenStudy (solomonzelman):

I deleted, b/c I misread the q.

OpenStudy (solomonzelman):

find the slope of a perpendicular line. plug in the slope that you get and the point shown for b, into y=mx+b

undeadknight26 (undeadknight26):

so far i have y = -5x + -1?

OpenStudy (solomonzelman):

for the first line?

undeadknight26 (undeadknight26):

I got that from the graph.

OpenStudy (solomonzelman):

I'll walk you through this, ready?

undeadknight26 (undeadknight26):

Yea.

OpenStudy (solomonzelman):

I am going to be posting short replies for you to have time to process the work. Pick any two point on your line, lets say (1,4) and (0,2)

undeadknight26 (undeadknight26):

ok.

OpenStudy (solomonzelman):

Slope formula is \[\frac{y_1-y_2}{x_1-x_2}\] plug in your two points into the slope formula, \[slope=\frac{4-2}{1-0}-->\frac{2}{1}-->2\]

undeadknight26 (undeadknight26):

so what other point do it have in this that...

undeadknight26 (undeadknight26):

-5, -1 is the first one right?

OpenStudy (solomonzelman):

Hold on, are you following so far?

undeadknight26 (undeadknight26):

yes take to points.. and put them in that formula form right?

undeadknight26 (undeadknight26):

2*

OpenStudy (solomonzelman):

The y intercept of the line or the "b" is the point on the line that lays on the 0-x-axis. in your case you don't even have to plug in 0 for x to find it, because it is graphed. You can clearly see that this point is (0,2) so the y intercept is 2.

OpenStudy (solomonzelman):

Knowing that slope is 2 and y intercept is 2, you have (for this, the first line) y=2x+2

undeadknight26 (undeadknight26):

so 2 - -1 and 2 - -5?

OpenStudy (solomonzelman):

To find a slope of a perpendicular line you have to take the slope of the (initial/first) line take the multiplicative inverse divide by '-1' for slope s, perpendicular slope is -1/s.

OpenStudy (solomonzelman):

so you know that it will be y=-1/2x+b, find the y intercept by plugging in your point (-5,-1)

undeadknight26 (undeadknight26):

so y = -.5x + b?

OpenStudy (solomonzelman):

plug in your point (-5,-1) to find b.

undeadknight26 (undeadknight26):

so: -1 = .5 x -5 + b?

undeadknight26 (undeadknight26):

BUT to find out B it would be: B = .5/5 - -1?

undeadknight26 (undeadknight26):

b = 11?

undeadknight26 (undeadknight26):

so .5 x -5 + 11 = y?

undeadknight26 (undeadknight26):

so y = 13.5?

OpenStudy (solomonzelman):

|dw:1383857098617:dw| makes sense, right?

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