Write the slope-intercept form of the equation parallel to y = 7x + 2, which passes through the point (1, -3).
@tafkas77
Okay. This one is going to be a LOT like the one we just covered. First things first, though: Do you know what parallel lines have in common?
Yeah I think so.
Well, just to be sure... :) Parallel lines have the SAME slope. So if we're looking for an equation that has a line parallel to the equation they gave you, all we need to have is the same slope! In this case, what would our slope be? (Hint: Look for the "m" in y = 7x + 2)
the m is 7
Perfect. So now we can move on to our list of steps. What should we do first, since we know our slope and our equation (y = mx + b)?
we plug in the slope.
Right. :) y = 7x + b Okay, what should our next step look like?
we plug in the x and y intercepts. -3 = 71 + b?
oops -3 +7(1) +b
Correct. :) Now, we have to simplify the equation: -3 = 7 + b What happens next?
-3 = 7 + b
oh wait
we get b alone.
Exactly. And how do you do that?
I dont know. im a little stuck.
That's all right. :) Well, to get 'b' alone, you want to CANCEL OUT any numbers that 'b' is with. :) Let's look at what we've got... -3 = 7 + b Well, we need to get rid of 7. We want to banish 7 to the other side of the equation. But how?
i dont know.
We'll add a -7 to both sides, because whatever you do to one side, you do to the other. -7 - 3 = 7 - 7 + b
7 plus -7 equals zero, so that means 'b' gets a little fresh air, know what I mean? Haha, does this make sense?
yeah it does.
Great! So can you simplify -7 - 3 = 7 - 7 + b
-10 = 0 + b
Perfect. So b = -10. Now we know both the slope (7) and the y-intercept (b). Can you solve the original equation (y = mx + b) now?
so the answer is y= 7 + -10
y = 7 -10
Very close. Hey, whenever you see y = mx + b think of it as y = mx +/- b, okay? :) And leave the x in there, so you're still following the format (like you did last time): y = 7x - 10 Awesome work!
thanks for your help! :D
No problem! (Pun totally intended, hehe) :)
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