Question

How do you graph f(x)=(x-9)squared + 2

Answer 1

you'll want to use the 'vertex form' of a parabola to help understand where to graph this at.
does
y=a(x-h)^2 + k
look familiar?

Answer 2

yes but im having trouble graphing it

Answer 3

ok, so what do you get for the vertex of the parabola?

Answer 4

I got 9,2 for my vertex

Answer 5

great,
so we can tell if the parabola is going to open up or down if the 'a' term is positive or neagative:
if +a then opens up
if -a then opens down

Answer 6

I have that, but im not sure if my slope is right.. How do I find a?

Answer 7

y =a(x-h)^2 + k
f(x)=(x-9)^3 + 2

do you see where 'a' is for your equation? and what it is?

Answer 8

No I dont know what a is.. is it x? therefore 1/1?

Answer 9

f(x)=(x-9)^3 + 2
is the same as
f(x)=1*(x-9)^3 + 2
so a = 1
and 'a' is positive, so the parabola opens up,

Answer 10

we know the vertex and that the parabola opens up,
the next thing to do is to input some numbers for x and see what y becomes.
since we know the vertex is at (9,2) i'd us an x value of +1 and -1 from the x value 9, and see what y's I get, and plot those points

Answer 11

Okay thanks I got the answer, I will give you medals

Answer 12

thx