Question

Please help me simplify... I'll be back in 40 min

Answer 1

\[3(a^2 b) ^ -3 / (3ab)^2 \] i forgot how to write the -3 power correctly.

Answer 2

\[\frac{ 3(a^2b)^-3 }{ (3ab)^2 }\] that's a little clearer. :)

Answer 3

ok ill try one more time to use this equation editor... \[\frac{ 3(a^2b)^{-3} }{(3ab)^2 } \]

finally, now could someone simplify this please c?

Answer 4

I can type out my own working if you reakllyh want me to ?

Answer 5

is the bottom \[9a^2b^2\]

Answer 6

You have two rules here
(1) When you take an exponent of an exponent they multiple
\[{(A)^2}^{5} = (A)^{2*5}\]
(2) When you have an exponent being divided by another exponent they subtract
\[\frac{A^8}{A^4} = A^{8-4}\]\

Use these rules and match the numbers with the same base

Answer 7

thank you. grat answer.

Answer 8

Look :
we have :
(a^2b)^-2 = a^2*(-2) * b ^-2 = a^-4 * b^-2
3( a^-4 * b^-2 ) = 3a^-4 * b ^ -2
got it ?

Answer 9

then :
( 3ab)^2 = 3^2 * a^2 * b ^2 = 9a^2B^2
have :
3a^-4 * b ^ -2/9a^2B^2 = 3a^-4/9a^2 * b^-2/b^2 = a^-4/3a^2 * b^-4 = 1/3 * a^-6 * b^-4
Got it ?;)

Answer 10

i GOT \[\frac{ 3(a^{-6}*b ^{-3}) }{ 9a^2b^2 }\]= \[\frac{ 1*a ^{-6-2}b ^{-3-2} }{ 3 } \] =
\[\frac{ 1 }{ 3a^8b^5 }\] so I may have mucked it up, but i think I followed your rules ?