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Calculus help please! Medal & fan if I'm not already! :)
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You can write 1+cos t as 1+cos 2(t/2). Now apply cos 2t formula below. Also apply sin 2t on top like this.
Use L -Hopsital if you know
What is L-Hospital?
Am I missing something? \[\cos 0 = 1\]Why can't you just evaluate this with substitution and call it a day?
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\[\Large \frac{\sin t}{1+\cos t}=2 \frac{\sin \frac{t}{2} \cos \frac{t}{2}}{2 \cos^2 \frac{t}{2}}\] it will be 0
lol yeah no need to do anything just put 0 :P 0/1=0
@SACAPUNTAS is right!!
Thanks Everyone!
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