A quadrilateral contains two equal sides measuring 12 cm each with an included right angle. If the measure of the third side is 8 cm and the angle opposite the right angle is 120 degrees, find the fourth side and the area of the quadrlateral.

Question

anonymous · Answer

draw it: 

make a-b-c be right angle with sides 12cm long and 90deg between them 
make d be point that is somewhere between a and c but 8cm from c. 
distance abc is right angle triangle with hypotenuse ac=12*sqrt(2). 
then using cosine law we find missing side. note that there will be two solutions: 

b^2 = a^2 + c^2 - 2ac*cos(120)

anonymous · Answer

I can't draw it that's the problem =.=

anonymous · Answer

The corresponding diagonal of the quadr. is rt288. 
Now let fourth side be x. Use cosine rule and you get. 
288 = 64 + x^2 - 2(8)cos120. Which leads you to x = 4+16rt15. 
Now use sine rule to find the area of each triangle and add them.

anonymous · Answer

fig please  =.=

directrix · Answer

Here is the problem or a similar as worked here a few days ago. http://openstudy.com/study?#/updates/5275f0c5e4b0f6d98a1f7ae9