The graph shows the velocity-time graph of a particle as it passes a point O. After passing O, when does the particle have the smallest displacement and what is the value of the smallest displacement?
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do u know how to calculate displacement in VT graph?
By finding the areas under the curve?
correct!.. but.. the question is kinda confusing.. its asking for smalleest displacement displacement depends on time.. .. so is it like you have to consider a specific period of time or something? :-/
The answer given is 40.9 m.
so at time t=0 , the particles passed the point 0 ?
Not sure
then the question isn't worded properly .. atleast i don't get the question :P
@AllTehMaffs
It's weird :P I think they do want you to assume that point 0 is at t=0 because t is the x-axis. area under the curve is right: They want you to compare the areas of \[0s<t<8s \\ 8s<t<11s \\ 11s<t<15s\] so for the little bit on the far right \[ \text{base}=2s \quad; \quad \text{height} = -10/3 \ m/s\] giving the area as \[ \text{displacement}= \ 2 \Big(\frac{1}{2}bh\Big)\] Then you can compare it to the big rectangle, and the other triangle to see which gives you the greatest displacement. (magnitude)
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