integral of -12 / (4+x^2) dx
I am not sure if this is would apply to a rule or not...but I get confused with these type of problems.
my brain is malfunctioning and I appear to be useless. I'm very sorry :P @Mashy can you help?
This appears to be a standard integral.. of the form \[\int\limits_{}^{}\frac{1}{x^2+a^2} dx\] u know the solution to that? or u want me to help u derive it?
could you help me?
sure.. use a trignometric substitution.. we ll derive the answer for the general case that i put up.. then u can apply it to your probelm so what trignometric substituition can u think of?
would it be (1/a)tan-(a/u)+C?
ohw wow :P.. u directly gave the answer.. did u look it up somewhere? or u just did the whole thing in ur head? :D
it is a rule that the teacher gave us... so would it be -6xtan-(2/x) +C?
IT IS (X/2)?
well yea.. \[\int\limits_{}^{}\frac{1}{x^2+a^2}dx = \frac{\tan^{-1}(\frac{x}{a})}{a}\] so just substitute now :P.. and see for yourself what the answer would be!
Yes, but then I would have to find a number that I can multiply so it can equal -12 on the top...
just take -12 out of the integral.. keep it separate and after integrating do the algebra!!..
and its (X/2)!
okay! so I get -6tan-(x/2) +C
yes.. thats right!
YAY! THANK YOU!
your welcome!
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