please explane the answer and get medal
Figure ABCD is a trapezoid with point A (0, -4). What rule would rotate the figure 270° clockwise, and what coordinate would be the output for point A'?
(x,y)→(y,-x); A' (-4, 0) (x,y)→(-y,x); A' (4, 0) (x,y)→(y,x); A' (-4, 0) (x,y)→(-y,-x); A' (4, 0)
thanks
i know
donti have to use the 180 rule or omeething
why not
ho said that i have given a answer before
is the answer (x,y)→(y,-x); A' (-4, 0)
ho is te admin
-4,0 is the results lets see if the rule is good: (0,-4) -> (-4,0) cant tell with that zero in the way :/
id test it on a different point: 1,1 270s to 1,-1 ... thats better
lol, 0,4 seems simpler too
amistre, you have a valid point, the zero doesn't narrow it down
the correct answer was (x,y)→(-y,x); A' (4, 0)
oh gosh darn, i went counterclockwise
thanks for explaining it
if you go 90 counter clock 3 time then you get the correct answer
is that the answer?
because the rule for counter clock is -y,x
i think it is correct whn i sumit i will send message
bye
oh i see clockwise 270 degrees = 90 counterclockwise degrees
and the rule for a clockwise rotation of 90 degrees is (x,y) -> (-y,x)
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