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Mathematics 22 Online
OpenStudy (anonymous):

please explane the answer and get medal

OpenStudy (anonymous):

Figure ABCD is a trapezoid with point A (0, -4). What rule would rotate the figure 270° clockwise, and what coordinate would be the output for point A'?

OpenStudy (anonymous):

(x,y)→(y,-x); A' (-4, 0) (x,y)→(-y,x); A' (4, 0) (x,y)→(y,x); A' (-4, 0) (x,y)→(-y,-x); A' (4, 0)

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

i know

OpenStudy (anonymous):

donti have to use the 180 rule or omeething

OpenStudy (anonymous):

why not

OpenStudy (anonymous):

ho said that i have given a answer before

OpenStudy (anonymous):

is the answer (x,y)→(y,-x); A' (-4, 0)

OpenStudy (anonymous):

ho is te admin

OpenStudy (amistre64):

-4,0 is the results lets see if the rule is good: (0,-4) -> (-4,0) cant tell with that zero in the way :/

OpenStudy (amistre64):

id test it on a different point: 1,1 270s to 1,-1 ... thats better

OpenStudy (amistre64):

lol, 0,4 seems simpler too

OpenStudy (perl):

amistre, you have a valid point, the zero doesn't narrow it down

OpenStudy (anonymous):

the correct answer was (x,y)→(-y,x); A' (4, 0)

OpenStudy (perl):

oh gosh darn, i went counterclockwise

OpenStudy (anonymous):

thanks for explaining it

OpenStudy (anonymous):

if you go 90 counter clock 3 time then you get the correct answer

OpenStudy (perl):

is that the answer?

OpenStudy (anonymous):

because the rule for counter clock is -y,x

OpenStudy (anonymous):

i think it is correct whn i sumit i will send message

OpenStudy (anonymous):

bye

OpenStudy (perl):

oh i see clockwise 270 degrees = 90 counterclockwise degrees

OpenStudy (perl):

and the rule for a clockwise rotation of 90 degrees is (x,y) -> (-y,x)

OpenStudy (perl):

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