What does this mean ? cos θ > 0
what does this mean x > 3
x is greater than three
so , cos theta is greater than zero, what about it?
90> θ>0 then cosθ>0
is it in Quadrant 1 ? @nonamenever
yep
what is the question exactly?
cos(x) > 0 in the interval (-pi/2, +pi/2) Since cos is a periodic function, you can add any integer multiple of 2pi to the above interval and cos will be > 0.
Find the exact value of the expression. sin θ = − 1/ 5 and cos θ > 0; find tan θ.
sin(x) = -1/5 = -0.2 x = -11.54 degrees cos(-11.54) = 0.98 tan(x) = sin(x) / cos(x) = -0.2 / 0.98 = ?
in the sample problem , the answer is a fraction in radian form. they did not solve for the angle
which I assume,
There are different ways of solving the same problem and arriving at the same answer. You can draw a right angle and arrive at the same answer: |dw:1383837589381:dw|
Here they are asking for tan(x) so the answer will not be in radians. It will be a number. If they ask for x (or theta) then the answer will be in radians or degrees.
Without solving for the angle this is how you can find tan(x) in the diagram. They have given you sin(x) = -1/5. Sin(x) is opposite / hypotenuse which I have drawn and I have put a negative sign denoting a negative angle x. The side marked with a question is: sqrt(5^2 - (-1)^2) = sqrt(24) tan(x) = opposite / adjacent = -1 / sqrt(24) = -sqrt(24)/24 = sqrt(6)/12
@ranga I salute you ! thanks!
you are welcome.
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