Question

determine whether the function is odd, even or neither?
k(x)=3-7(sqrt1+x^2)

Answer 1

\[3-\sqrt{1+x^2}\]

Answer 2

\[3-7\sqrt{1+x^2?}\]

Answer 3

????????
@lukecrayonz

Answer 4

Oh right sorry 1 sec

Answer 5

Ok so input -x for everytime you see x, and tell me what you get.

Answer 6

If f(–x) = f(x), all of the signs are the same, then the function is even. If you end up with the exact opposite of what you started with (that is, if f(–x) = –f(x), so all of the "plus" signs become "minus" signs, and vice versa), then the function is odd

Answer 7

And if you get neither answer, then it's neither! :P

Answer 8

Ok h(x)=\[3-7\sqrt{1+(-x)^2}\]

Answer 9

So it's even.

Answer 10

ok thanks

Answer 11

there is another one

please

Answer 12

Sure :-)

Answer 13

h(x)=x(4-x^2)

Answer 14

Odd :-)

Answer 15

h(-x)=-x[4-(-x)^2]

Answer 16

so....

Answer 17

what next ??

Answer 18

??????????????????

Answer 19

@lukecrayonz

Answer 20

if f(–x) = –f(x), so all of the "plus" signs become "minus" signs, and vice versa), then the function is odd